Cos[2/5兀（x-11)]

定积分（兀/2到-兀/2）根号cos^3x-cos^5xdx定积分（兀/2到-兀/2）根号cos^3x-cos^5xdx定积分（兀/2到-兀/2）根号cos^3x-cos^5xdx

2sin^2x-5sinxcosx=3cos^2x,求X,2sin^2x-5sinxcosx=3cos^2x,求X,2sin^2x-5sinxcosx=3cos^2x,求X,因式分解一下得到（sinx-3cosx)(2sinx+cosx)=

f(x)=cos(2兀-x)cos(2/兀-x)-sin方x化简速求f(x)=cos(2兀-x)cos(2/兀-x)-sin方x化简速求f(x)=cos(2兀-x)cos(2/兀-x)-sin方x化简速求f(x)=cos(2兀-x)cos(

已知cos(π/2+x)=sin(x-π/2)求sin^3(π-x)+cos(x+π)/5cos(5π/2-x)+3sin(7π/2-x)已知cos(π/2+x)=sin(x-π/2)求sin^3(π-x)+cos(x+π)/5cos(5π

化简sin(x)(cos(x)+cos(3x)+cos(5x)+cos(7x))化简sin(x)(cos(x)+cos(3x)+cos(5x)+cos(7x))化简sin(x)(cos(x)+cos(3x)+cos(5x)+cos(7x))

cosx是偶函数,cosx=cos-xcos(2x+5)=cos(-2x+5)还是=cocosx是偶函数,cosx=cos-xcos(2x+5)=cos(-2x+5)还是=cos(-2x-5)cosx是偶函数,cosx=cos-xcos(2

(1/2)高一数学：(cos(x)^4-5cos(x)^2+1)/(2cos(x)^2-1)求值域怎么求啊,要过程,答案是(-1,正无穷)U((1/2)高一数学：(cos(x)^4-5cos(x)^2+1)/(2cos(x)^2-1)求值域

化简cos2x化简cos2x化简cos2xcos是2分之根号2在把数据代入计算就等于根号2x

(cos(x))^-2导数(cos(x))^-2导数(cos(x))^-2导数-2(cosx)^(-3)(-sinx)=2sinx(cosx)^(-3)[-2(cos(x))^-3]*(-sinx)利用复合函数的求导法则：y=[cos(x)

cos(x^2)dxcos(x^2)dxcos(x^2)dx1/3*-sin(x^3)微分啊，这个微分很简单的，一元函数的微分和导数是一样的，只是在后面加个dx,前面的函数是复合函数，先对cos()求导，在对里面的那部分求导，得出-sin(

cosx>-1/2cosx>-1/2cosx>-1/2画出y=cosx在[-π,π]的图像,由于cos(-2π/3)=cos(2π/3)=-1/2于是在[-π,π]内,由cosx>-1/2得-2π/3

证明cos2xcosx=1/2(cosx+cos3x)证明cos2xcosx=1/2(cosx+cos3x)证明cos2xcosx=1/2(cosx+cos3x)证明：等式右边=1/2(cosx+cos2x*cosx-sin2x*sinx)

三角化简sin(x-5兀)cos[(-兀/2)-x]cos(8兀-x)/sin[x-(3兀/2)]sin(-x-4兀)三角化简sin(x-5兀)cos[(-兀/2)-x]cos(8兀-x)/sin[x-(3兀/2)]sin(-x-4兀)三角

求cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)求值:cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)(5/24)(11/24)=5/11

cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)cos(π/11)cos(2π/11)cos

已知cos2x=3/5,求sin^4x+cos^4x的值已知cos2x=3/5,求sin^4x+cos^4x的值已知cos2x=3/5,求sin^4x+cos^4x的值cos2x=3/5,sin2x=±4/5sin^4x+cos^4x=（-

求值:cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)求值:cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)求值:cos(π/11)cos(

一道算术题目↓↓x^2=5-4cosαx^2=25-24cosβcosα+cosβ=0求X值一道算术题目↓↓x^2=5-4cosαx^2=25-24cosβcosα+cosβ=0求X值一道算术题目↓↓x^2=5-4cosαx^2=25-24

已知x属于(3兀/2,2兀),且cos(3兀/2+x)=-3/5,则cos(x-3兀/4)的值是多少给出计算过程,已知x属于(3兀/2,2兀),且cos(3兀/2+x)=-3/5,则cos(x-3兀/4)的值是多少给出计算过程,已知x属于(

为什么cos(2x-π/3)-sin(5π/6)=cos(2x-π/3)?为什么cos(2x-π/3)-sin(5π/6)=cos(2x-π/3)?为什么cos(2x-π/3)-sin(5π/6)=cos(2x-π/3)?不科学啊,你确定题