已知x=y+2,求[(x+y)(x-y)-(x-y)的2次方+2y(x-y)]÷4y的值
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已知x=y+2,求[(x+y)(x-y)-(x-y)的2次方+2y(x-y)]÷4y的值
已知x=y+2,求[(x+y)(x-y)-(x-y)的2次方+2y(x-y)]÷4y的值
已知x=y+2,求[(x+y)(x-y)-(x-y)的2次方+2y(x-y)]÷4y的值
x=y+2
所以x-y=2
原式=(x²-y²-x²+2xy-y²+2xy-2y²)÷4y
=(-4y²+4xy)÷4y
=x-y
=2
式子化简结果为x-y,因为已知x=y+2,则x-y=2,所以结果为2.
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