y=sin(π/3-2x)+cos(2x)的周期怎么求?

化简y=sin^2(x)+2sin(x)cos(x)+3cos^2(x) y=(sin x + COS x)^2 y =(cos^2) x - sin (3^x),求y' y=2cos x (sin x+cos x) Sin x-sin y=2/3 cos x-cos y=1/2 求cos(x-y) 已知sinx=3/5,x∈(π/2,π),求【sin(x+y)+sin(x-y)】/【cos（x+y）+cos（x-y）】的值 sin(x+y)sin(x-y)=k,求cos^2x-cos^2y 当cos^2x-cos^2y=√3/2时,求sin(x+y）×sin(x-y) 证明COS（X+Y）COS（X-Y）=COS^2X-SIN^2Y 证明cos(x+y)cos(x-y)= cos^2(x)-sin^2(y) 求y=sin＾2(x)+3sin(x)cos(x)-2cos＾2(x)的最大值 y=sin^2(x)+2sin(x)cos(x)+3cos^2(x)的最值 用向量解 求y=sin x +2sin x cos x -3cos²x 的周期和值域, y=2cos(x/4+ π/3)-3sin(x- π/4)y=sin(4x- π/3)-cos(3x+π/2) cos(x-y/2)=-1/9,sin(x/2-y)=2/3,π/2 1.y=sin(-X+π/6)2.y=cos(-2X+π/3) 求导：y=x-sin(x/2)cos(x/2). 函数y=sin(2x+α)cos(x+α)-cos(2x+α)sin(x+α)在x=π/3处的导函数为