(x-y-1)(x+y-1)(a-2b)( )=-[ (2b)平方-a平方]x+y=m,xy=n,x平方+y平方=

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(x-y-1)(x+y-1)(a-2b)(       )=-[ (2b)平方-a平方]x+y=m,xy=n,x平方+y平方=

(x-y-1)(x+y-1)(a-2b)( )=-[ (2b)平方-a平方]x+y=m,xy=n,x平方+y平方=
(x-y-1)(x+y-1)
(a-2b)(       )=-[ (2b)平方-a平方]
x+y=m,xy=n,x平方+y平方=        

(x-y-1)(x+y-1)(a-2b)( )=-[ (2b)平方-a平方]x+y=m,xy=n,x平方+y平方=
(x-y-1)(x+y-1)
=(x-1)^2-y^2
=x^2+1-2x+y^2
(a-2b)(a+2b)=-[(2b)^2-a^2]
a^2-4b^2=a^2-4b^2
x+y=m,xy=n,x^2+y^2=x^2+y^2+2xy-2xy=(x+y)^2-2xy=m^2-2n

因式分解:(1)、(2a-3b)(7x+y)+(x-5y)(3b-2a)(2)、(x+y)^3(x+y)^2-(-x-y) 1.x(x-y)+y(y-x)2.9(a-b)^2-16(a+b)^2 3.25(x-y)^2+10(y-x)+1 [1]a(x-2y)-b(2y-x)+d(2x-4y) [2]x平方-2xy+y平方-2x+2y+1 【3】一(a-x)(a-y)-x(y-a)(X-a)[1]a(x-2y)-b(2y-x)+d(2x-4y) [2]x平方-2xy+y平方-2x+2y+1【3】一(a-x)(a-y)-x(y-a)(X-a) 分解因式,急求! (x/2y)^2*y/2x-x/y^2/2y^2/x(x/x+y+2y/x+y)*xy/x+2y/(1/x+1/y)(1/a+1/b)^2/(1/a^2-1/b^2) (1)2x(x+y)-4(x+y)^2.(2)(x+y)(b-a)+(x-y)(a-b)的分解因式解答过程 A={(X,Y)|X+Y>=1},B={(X,y)|X^2+y^2=1},B={(X,y)|X^2+y^2 ab^2(x+y)^p+a^2b(x+y)^(p+1) x(x^2-y^2)-y(x-y)^2 因式分解 (1)6(x-y)^3-3y(y-x)^2 (2)x(x-y)(a-b)-y(y-x)(因式分解(1)6(x-y)^3-3y(y-x)^2(2)x(x-y)(a-b)-y(y-x)(b-a)(3)(a+b)(a+b-1)-a-b+1 1(x-3x-1)(x+3y-1)2(3x-2y+1/4)²3(a+b)²-(a-b)²4 [2x²-(x+y)(x-y)][(-x-y)×(y-x)+2y²],其中x=1 y=25[(0.5x-y)²+(0.5x+y)²](0.5x²-2y²)6(a+3b)²-2(a+3b)(a-3b)+(a-3b)²7 分解因式:(1)25x²-y²; (2)(a-b)(x-y)+(a-b)(x+y) (3)(x+2y)²-8xy 设A={(x,y)|x-2y=1},B={(x,y)|x+2y=3},求A∩B.帮帮小妹啦! 设A={(X,Y)|X—2Y=1},B={(X,Y)|X+2Y=3},求A∩B 设A={(x,y)|x-2y=1},B={(x,y)|x+2y=3},求A∩B. 已知集合A={(x,y)|3x+2y=1},B={(x,y)|x-y=2},求A∩B 设a={(x,y)|2x-y=1},b={(x,y)|2x+y=0},求a∩b 设A={(x,y)丨2x+y=1},B={(x,y)丨x-2y=2},求A交B 已知集合A={(x,y)丨2x-y=1},B={(x,y)丨x+2y=2},试求A∩B 设集合A={(x.y)|2x+y=1},B={(x.y)|x-2y=2},求A∩B