y=∫[H-R(sin(θ+φ)-sin(θ))]sin(θ)dθ怎么解啊

y=∫[H-R(sin(θ+φ)-sin(θ))]sin(θ)dθ怎么解啊
y=∫[H-R(sin(θ+φ)-sin(θ))]sin(θ)dθ怎么解啊

y=∫[H-R(sin(θ+φ)-sin(θ))]sin(θ)dθ怎么解啊
[H-R(sin(θ+φ)-sin(θ))]sin(θ)
=Hsinθ-Rsinθsin（θ+φ）-sinθsinθ
=Hsinθ-R/2〔cos（2θ+φ）-cosφ〕-1/2（1-cos2θ）
=Hsinθ-R/2cos（2θ+φ）+1/2cos2θ+Rcosφ/2-1/2
y=∫（Hsinθ-R/2cos（2θ+φ）+1/2cos2θ+Rcosφ/2-1/2）dθ
=-Hcosθ-R/4sin（2θ+φ）+1/4sin2θ+（Rcosφ/2-1/2）θ+C