计算：[（2x+1)/(x²+x-2）]-[（x-2）/（x²-4）]如题

计算：[（2x+1)/(x²+x-2）]-[（x-2）/（x²-4）]如题
计算：[（2x+1)/(x²+x-2）]-[（x-2）/（x²-4）]
如题

计算：[（2x+1)/(x²+x-2）]-[（x-2）/（x²-4）]如题
[(2x+1)/(x²+x-2)]-[(x-2)/(x²-4)]
=(2x+1)/[(x+2)(x-1)]-(x-2)/[(x+2)(x-2)]
=(2x+1)/[(x+2)(x-1)]-1/(x+2)
=(2x+1)/[(x+2)(x-1)]-(x-1)/[(x+2)(x-1)]
=[(2x+1)-(x-1)]/[(x+2)(x-1)]
=(x+2)/[(x+2)(x-1)]
=1/(x-1)

=(2x+1)/(x+2)(x-1)-(x-2)/(x+2)(x-2)
=(2x+1)/(x+2)(x-1)-1/(x+2)
=(2x+1-x+1)/(x+2)(x-1)
=(x+2)/(x+2)(x-1)
=1/(x-1)

您好：
[（2x+1)/(x²+x-2）]-[（x-2）/（x²-4）]
=（2x+1）/(x+2)(x-1)-(x-2)/(x+2)(x-2)
=(2x+1)/(x+2)(x-1)-1/(x+2)
=(2x+1-x+1)/(x+2)
=(x+2)/(x+2)
=1


如果本题有什么不明白可以追问，...

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您好：
[（2x+1)/(x²+x-2）]-[（x-2）/（x²-4）]
=（2x+1）/(x+2)(x-1)-(x-2)/(x+2)(x-2)
=(2x+1)/(x+2)(x-1)-1/(x+2)
=(2x+1-x+1)/(x+2)
=(x+2)/(x+2)
=1


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