数列【an】满足(n+1)an+1=2(n+2)an+3n2+9n+6,a1=6,求通项公式

数列{an}满足a1=1 an+1=2n+1an/an+2n 数列｛an｝满足a1=1,且an=an-1+3n-2,求an 已知数列{an}满足an+1=2an+3.5^n,a1=6.求an 数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an 数列an满足a1=1/3,Sn=n(2n-1)an,求an 数列{an}满足a1=2,a(n+1)=2an+n+2,求an 已知数列{An}满足A1=1,An+1=2An+2^n.求证数列An/2是等差数列 设数列{an}满足an=2an-1+n 若{an}是等差数列,求{an}通项公式 已知数列an满足an=1+2+...+n,且1/a1+1/a2+...+1/an 数列an满足a1=1,a(n+1)=an/[(2an)+1],求a2010 已知数列{an}满足a1=1,an+1·an=2^n 则s2012 已知数列{an}满足a1=1/2,sn=n^2an,求通项an 数列[An]满足a1=2,a（n+1）=3an-2 求an 已知数列{an},满足a1=1/2,Sn=n²×an,求an 已知数列an满足a1=1/2 sn=n平方×an 求an 数列an满足a1=0,An+1=an+2n求a2009 已知数列An满足 A1=1/2 Sn=N²An 求An 已知数列an满足a1=1 Sn=2an+n 求an