作业帮(x-1/2)(2x+1)(2x^2+1/2)(4x^4+1/4)(16x^8+1/16)/(256x^16+1/256)=?3Q
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/10 08:51:10
(x-1/2)(2x+1)(2x^2+1/2)(4x^4+1/4)(16x^8+1/16)/(256x^16+1/256)=?3Q
(x-1/2)(2x+1)(2x^2+1/2)(4x^4+1/4)(16x^8+1/16)/(256x^16+1/256)=?3Q
(x-1/2)(2x+1)(2x^2+1/2)(4x^4+1/4)(16x^8+1/16)/(256x^16+1/256)=?3Q
（X-1/2)(2X+1)(2X^2+1/2)(4X^4+1/4)(16X^8+1/16)÷（256X^16-1/256) ＝{[(2X-1)(2X+1)]/2}(2X^2+1/2)(4X^4+1/4)(16X^8+1/16)÷（256X^16-1/256) =(4X^2-1)(2X^2+1/2)(4X^4+1/4)(16X^8+1/16)÷（256X^16-1/256) ={[(4X^2-1)(4X^2+1)]/2}(4X^4+1/4)(16X^8+1/16)÷（256X^16-1/256) =(16X^4-1)(4X^4+1/4)(16X^8+1/16)÷（256X^16-1/256) =(256X^8-1)(16X^8+1/16)÷（256X^16-1/256) =(65536X^16-1)/（256X^16-1/256) =256
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