如图,AB=AC,AD=AE,BE=CD,求证△ABD≌△ACE证明在△ABD和△ACE中AB=AC,BE=CD,AD=AE,∴△ABE≌△ACE(SSS)

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如图,AB=AC,AD=AE,BE=CD,求证△ABD≌△ACE证明在△ABD和△ACE中AB=AC,BE=CD,AD=AE,∴△ABE≌△ACE(SSS)

如图,AB=AC,AD=AE,BE=CD,求证△ABD≌△ACE证明在△ABD和△ACE中AB=AC,BE=CD,AD=AE,∴△ABE≌△ACE(SSS)
如图,AB=AC,AD=AE,BE=CD,求证△ABD≌△ACE
证明在△ABD和△ACE中AB=AC,BE=CD,AD=AE,∴△ABE≌△ACE(SSS)

如图,AB=AC,AD=AE,BE=CD,求证△ABD≌△ACE证明在△ABD和△ACE中AB=AC,BE=CD,AD=AE,∴△ABE≌△ACE(SSS)
∵AB=AC ∴∠B=∠C ∵BE=CD ∴BE-DE=CD-CE 即BD=CE 根据SAS ∴全等

图呢??