1.若3^a = 2,则log 3,8 - 2log 3,6的值是（ ） (A)a - 2 (B)3a - (1 + a)^2 (C)5a -2 (D)3a - a^2

log(2)3=a,则log(6)4=（ 若log₃2=a,则log₃8-2log₃6用a表示为?1.a-2 2.5a-2.3.3a-(1+a)² 4.3a-a²-1 若log₃2=a,则log₃8-2log₃6用a表示为?1.a-2 2.5a-2.3.3a-(1+a)² 4.3a-a²-1 1、若lg2=a,lg3=b,则lg√15=?（用a、b表达）2、若log(15)(5)=m,则log(15)(3)=(用m表示)3、log(2)(3)*log(3)(4)*log(4)(5)*log(5)(6)*log(6)(7)*log(7)(8）=?4、设log(3)(2)=log(2)(3^x),x=?这个对数函数我学的很不好,所以希望过 若log(根号3)a= -2log(3)7,则a=? 若log(2)3=(1-a)/a则log(3)12RT求详解 若3^a=2,则log(3)8-2log(3)6用a的代数式可表示? 已知log（14）7=a log(14)5=b 用ab表示log(35)70=log(3)4*log(4)8*log(8)m=log(4)2 求m 若log底数2[log底数3(log底数4)]若log底数2[log底数3(log底数4（x）)]=log底数3[log底数4(log底数2(y))]=log底数4[log底数2(log底数3z)]=0,则x+y+z= a,b,x 都是正数,4[log(a)x]²+[3log(b)x]²=8log(a)x*log(b)x,则a,b的关系 log(3)4*log(4)8*log(8)M =log(2)16 M是多少呃.... 关于数学对数的换底公式推论的问题已知 log(2)(3) = a,log(3(7)=b,用a,b表示log(42)(56)因为log(2)(3)=a,则1/a=log(3)(2),又∵log(3)(7)=b,∴log(42)(56)=log(3)(56)/log(3)(42)=log(3)(7)+3·log(3)(2)/log(3)(7)+log(3)(2)+1=ab+3/ab+b+1 关于数学对数的换底公式推论的问题已知 log(2)(3) = a,log(3(7)=b,用a,b表示log(42)(56)因为log(2)(3)=a,则1/a=log(3)(2),又∵log(3)(7)=b,∴log(42)(56)=log(3)(56)/log(3)(42)=log(3)(7)+3·log(3)(2)/log(3)(7)+log(3)(2)+1=ab+3/ab+b+1 等比数列a+log(2)3,a+log(4)3,a+log(8)3求公比q. 若log(a)2=m,log(a)3=n,则a^2m+n= 对数函数题 log a - log b = 3 log (c/2) 求 a = ______________ 1.若3^a = 2,则log 3,8 - 2log 3,6的值是（ ） (A)a - 2 (B)3a - (1 + a)^2 (C)5a -2 (D)3a - a^2 log a 2/3