cos(π/6-a)=根号3/3 则sin(5π/6-2a)值

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cos(π/6-a)=根号3/3 则sin(5π/6-2a)值

cos(π/6-a)=根号3/3 则sin(5π/6-2a)值
cos(π/6-a)=根号3/3 则sin(5π/6-2a)值

cos(π/6-a)=根号3/3 则sin(5π/6-2a)值
sin(5π/6-2a)=sin(π/2+π/3-2a)
=cos(π/3-2a)
=[cos(π/6-a)]^2-[sin(π/6-a)]^2
=1/3-2/3
=-1/3

cos(π/6-a)=根号3/3
cos(π/3-2a)=2cos²(π/6-a)-1=2/3-1=-1/3
=sin[π/2-(π/3-2a)]=sin(π/6+2a)=-1/3

sin(5π/6-2a)=sin(π/6+2a)=-1/3