7x+9y+11z=68;5x+7y+9z=52

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7x+9y+11z=68;5x+7y+9z=52

7x+9y+11z=68;5x+7y+9z=52
7x+9y+11z=68;5x+7y+9z=52

7x+9y+11z=68;5x+7y+9z=52
是求x,y,z的正整数解码?
7x+9y+11z=68 (1)
5x+7y+9z=62 (2)
两方程相减得:
x+y+z=8 (3)
(3)乘7得:
7x+7y+7z=56 (4)
(1)减(3)除以2得:
y+2z=6 (5)
(3)-(5)得:
x-y=2 (6)
由(5),(6)得:
方程(1),(2)只有x=3,y=4,z=1;x=4,y=2,z=2两组解,带入符合题意.

(3,4,1)
(5,0,3)
(4,2,2)

7x+9y+11z=68;5x+7y+9z=52 ..1.x+y+z=26,2.4y+3z=7,y-z=1,3x+2z=17,x+2y-z=18 9x-7y=173.x-7y+3z=17 4.2x+4y+3z=95x-6y-z=24 3x-2y+5z=113x+7y-2z=1 5x-6y+7z=131.x+y+z=26,y-z=1x+2y-z=18 2.4y+3z=7,3x+2z=11,9x-7y=17 3.x-7y+3z=17 5x-6y-z=24 3x+7y-2z=14.2x+4y+3z=93x-2y+5z=11 5x-6y+7z=13 4x+9y=12 3y-2y+5z=11 5x-6y+7z=13 求:x y z等于多少 X、Y、Z是三个非零自然数,且X乘6/5=Y乘8/7=Z÷10/9,那么X、Y、Z按照从小到大排列是 A、X>Y>Z B、Z>X>Y 6x+3y-2z=108,9x+7y-3z=212,3x-2y+5z=38,求x,y,z 三元一次方程解 1.{x+y-z=5 {3x+2y+z=2 {2x-2y+z=-31.{x+y-z=5 2.{9x-5y+x=-6 3.{x-y=3 4.{x+y=3 5.{4x-2y+z=7{3x+2y+z=2 {9x+y-2z=3 {x+z=7 {y+z=4 {2x-y-3z=28{2x-2y+z=-3 {-9x+3y-5z=0 {y-z=6 {z+x=5 {x+y-2z=13 解下面三元一次方程组9x-5y+z=5 9x+y+4x=14 -9x+3y-5z=-11 3x-5y+2z=14x+5y-z=5x-5y+3z=-24x+3y-2z=-7 5x-6y+z=-2 2x+z=-2 5x-3y+6z=-3 2x-y+3z=0 y+3z=6 3x+2y 2x+y x-y+1 ----- - ---- = ----- 4 5 6 初二数学三元一次方程计算题应用题求解, 3x-y+2z=3 2x+y-3z=11 x+y+z=12 3x-4z=7 2x+3y+z=9 5x-9y+7z=8 y=2x-7 5x+3y+2z 3x-4z=2 2x-y+2z=8 y+2z=-2 3x+y-4z=1x+y-z=11 y+z-x=5 三元一次方程:x+3y+2z=2 3x-y+2z=3 3x+2y-4z=3 2x+y-3z=11 2x-y=7 x+y+z=12还有:7x+2y-z=76x-y+z=74x+3y+z=9 好了,2x+y-3z=11 2x-y=7x+y+z=12 三(四)元一次方程组!1.2z-6=-2(x+3y)3(5y+x)=6-7z4(x+z)=9+9y2.2x-5y=-117y+4z=55x+2z=23.0.4x+0.3y-0.2z=40.6x-0.5y+0.3z=50.3x+0.2y+0.5z=224.x/2+3y/4+5z/3=455.1x+6y/5-4z=150.1x-0.4y+4z/5=55.x+y=7y-z=1z+2u=4u-3x=-11 2X+4y+3z=9 3x-2y+5z=11 5x-6y+7z=13 2x+4y+3z=9 3x-2y+5z=11 5x-6y+7z=13 解三元一次方程组{2x+4y+3z=9 3x-2y+5z=11 5x-6y+7z=13} 解这个三元一次方程 2x+4y+3z=9 3x-2y+5z=11 5x-6y+7z=13 2x+4y+3z=9① 3x-2y+5z=11② 5x-6y+7z=13③ 2x+4y+3z=9 3x-2y+5z=11 5x-6y+7z=13 这个方程怎么解? 求解三元一次方程组{2x+4y+3z=9 3x-2y+5z=11 5x-6y+7z=13} 方程组2x+4y+3z=9,3x-2y+5z=11,5x-6y+7z=13的解是什么