已知a=log3 2 ,用a表示log3 8-2log3 6是 ?

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已知a=log3 2 ,用a表示log3 8-2log3 6是 ?

已知a=log3 2 ,用a表示log3 8-2log3 6是 ?
已知a=log3 2 ,用a表示log3 8-2log3 6是 ?

已知a=log3 2 ,用a表示log3 8-2log3 6是 ?
log3 8-2log3 6
= 3log3 2 - 2(log 3 3 + log 3 2)
= 3log3 2 - 2(1 + log3 2)
= log 3 2 - 2
= a - 2

log3 8-2log3 6
=3log32-2(1+log32)
=3a-2-2a=a-2

a+2

log3 8-2log3 6
=log3(2^3)-2(log3 2 +log3 3)
=3log3 2-2(log3 2 +1)
=3a-2(a+1)
=a-2

因为a=log(3)2
所以原式=log(3)2^3-2*log(3)(2*3)
=3*log(3)2-2(log(3)2+1)
=3a-2(a+1)
=a-2