(1+0.228-0.21)×(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)×(0.228-0.21)简便解法这是预初一的题,但是不要告诉我去用计算机去做,

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/29 21:46:50
(1+0.228-0.21)×(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)×(0.228-0.21)简便解法这是预初一的题,但是不要告诉我去用计算机去做,

(1+0.228-0.21)×(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)×(0.228-0.21)简便解法这是预初一的题,但是不要告诉我去用计算机去做,
(1+0.228-0.21)×(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)×(0.228-0.21)简便解法
这是预初一的题,但是不要告诉我去用计算机去做,

(1+0.228-0.21)×(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)×(0.228-0.21)简便解法这是预初一的题,但是不要告诉我去用计算机去做,
(1+0.228-0.21)×(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)×(0.228-0.21)
=(1+0.228-0.21)×(0.228-0.21)+(1+0.228-0.21)×0.2003
-(1+0.228-0.21)×(0.228-0.21)-0.2003×(0.228-0.21)
=(1+0.228-0.21)×0.2003-0.2003×(0.228-0.21)
=0.2003× 【(1+0.228-0.21)-(0.228-0.21)】
=0.2003×1
=0.2003

(1+0.228-0.21)x(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)x(0.228-0.21) (1+0.228-0.21)×(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)×(0.228-0.21)为什么这么做啊(1+0.228-0.21)×(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)×(0.228-0.21)=(1+0.228-0.21)×(0.228-0.21)-(1+0.228- (1+0.228-0.21)×(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)×(0.228-0.21)简便解法这是预初一的题,但是不要告诉我去用计算机去做, (1+0.228-0.21)×(0.228-0.21+223)-(1+0.228-0.21+0.2003)×﹙0.228-0.21)(能巧算的就巧算) (1+0.228-0.21)×(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)×(0.228-0.21)简便运算,要写出具体过程 (1+0.228-0.21)*(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)*(0.228-0.21)巧算?写清思路 (1+0.228-0.21)*(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)*(0.228-0.21)要求简便运算 (1+0.228-0.21)*(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)*(0.228-0.21)如何巧算?写清巧算步骤. (1+0.228-0.21)x(0.228-0.221+0.2003)-(1+0.228-0.21+0.2003)x(0.228-0.21)怎么样巧算 (1+0..228-0.21)x(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)x(0.228-0.21)简便方法计算简便方法 巧算(2-1/2)×(2-2/3)×(2-3/4)×……×(2-2002/2003)巧算:(2-1/2)×(2-2/3)×(2-3/4)×……×(2-2002/2003)(1+0.228-0.21)*(0.228-0.21+0.20030)-(1+0.228-0.21+0.2003)*(0.228-0.21)解方程:7(x-3)=9+X21-x=1.5(9+x) (1+0.21+0.32)*(0.21+0.32+0.43)-(1+0.21+0.32+0.43)*(0.21+0.32) 坎贝尔太空计划0.22有MJ吗还有0.22和0.21的区别有什么 斗容量1m3正铲挖土机,挖四类土,装车,深度在2m内,小组成员两人,机械台班产量为4.76(定额单位100m3),则挖100m3的人工时间定额为( )工日.A.0.21 B.0.22 C.0.23 D.0.42 为什么选D (1+0.21+0.32)*(0.21+0.32+0.43)-(1+0.21+0.32+0.43)*(0.21+0.32)要怎么简算, 计算(1+0.21+0.32)x(0.21+0.32+0.43)-(1+0.21+0.32+0.43)x(0.21+0.2) 计算(1+0.21+0.32)x(0.21+0.32+0.43)-(1+0.21+0.32+0.43)x(0.21+0.2) 几道数学解方程和简便运算1.0.8:x=4/3 :0.22.(1/4 x+0.33)÷1/5=19.53.2.5×0.875+0.25×1.254.999 8/9+99 8/9+9 8/9+ 1/35.2.5-5/12-1/6÷2/7