作业帮关于弹簧简谐运动的物理问题.怎么在碰撞后求振幅?翻译见下A 2.00-kg object is attached to an ideal massless horizontal spring of spring constant 100.0 N/m and is at rest on a frictionless horizontal table.The spring is aligned a
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关于弹簧简谐运动的物理问题.怎么在碰撞后求振幅?翻译见下A 2.00-kg object is attached to an ideal massless horizontal spring of spring constant 100.0 N/m and is at rest on a frictionless horizontal table.The spring is aligned a
关于弹簧简谐运动的物理问题.怎么在碰撞后求振幅?
翻译见下
A 2.00-kg object is attached to an ideal massless horizontal spring of spring constant 100.0 N/m and is at rest on a frictionless horizontal table.The spring is aligned along the x-axis and is fixed to a peg in the table.Suddenly this mass is struck by another 2.00-kg object traveling along the x-axis at 3.00 m/s,and the two masses stick together.What are the amplitude and period of the oscillations that result from this collision?
大概就是一个2kg的物体连在一端固定的水平弹簧上,沿x轴运动,k＝100 无阻力.突然撞上一个沿x轴以3m／s 运动的2kg的小物块.这两个物块粘在一起运动,问周期和振幅.
周期求出来了是1.26,
关于弹簧简谐运动的物理问题.怎么在碰撞后求振幅?翻译见下A 2.00-kg object is attached to an ideal massless horizontal spring of spring constant 100.0 N/m and is at rest on a frictionless horizontal table.The spring is aligned a
首先要明题意：
一个质量为 m=2kg的物体与一个水平的轻质弹簧连接,静止地放在表面光滑无摩擦的水平桌面上,弹簧的另一端固定.以弹簧的方向为x轴,另一个质量为m= 2.0kg的物块以3.0m/s的速度沿x轴的方向突然撞上跟弹簧连接物体,碰撞后两物体粘合在一起沿x轴运动,求碰撞后系统周期和振幅.
周期：T=2π√2m/k=2π/5 s
振幅：在碰撞瞬间系统动量守恒：mv=2mv“,m=2.0kg,v=3m/s
解得：v”=1.5m/s
则系统总动能为：Ek=2mv^2/2=4.5 J
则有：kA^2/2=Ek
解得：A=0.30 m