已知abcd=1求1/(abc+ab+a+1)+1/(bcd+bc+b+1)+1/(cda+cd+c+1)+1/(dab+da+d+1)的值

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已知abcd=1求1/(abc+ab+a+1)+1/(bcd+bc+b+1)+1/(cda+cd+c+1)+1/(dab+da+d+1)的值

已知abcd=1求1/(abc+ab+a+1)+1/(bcd+bc+b+1)+1/(cda+cd+c+1)+1/(dab+da+d+1)的值
已知abcd=1求1/(abc+ab+a+1)+1/(bcd+bc+b+1)+1/(cda+cd+c+1)+1/(dab+da+d+1)的值

已知abcd=1求1/(abc+ab+a+1)+1/(bcd+bc+b+1)+1/(cda+cd+c+1)+1/(dab+da+d+1)的值
abcd=1
abc+ab+a+1=abc+ab+a+abcd=a(bc+b+1+bcd)=a(bc+b+abcd+bcd)=ab(c+1+acd+cd)=abc(1+abd+ad+d)
设x=abc+ab+a+1;
所以原式=1/x+a/x+ab/x+abc/x=(1+a+ab+abc)/x=1;
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